Inequality(VintasoftRectF,VintasoftRectF) Operator (VintasoftRectF)

In This Topic

Tests whether two VintasoftRectF structures differ in location or size.

Syntax

'Declaration

Public Operator <>( _
   ByVal leftThe VintasoftRectF structure that is to the left of the inequality operator.
 As VintasoftRectF, _
   ByVal rightThe VintasoftRectF structure that is to the right of the inequality operator.
 As VintasoftRectF _
) As Boolean

public bool operator =(
   VintasoftRectF left, 
   VintasoftRectF right
)

public: bool op_Inequality(
   VintasoftRectF left, 
   VintasoftRectF right
)

public:
bool operator =(
   VintasoftRectF left, 
   VintasoftRectF right
)

Parameters

left: The VintasoftRectF structure that is to the left of the inequality operator.
right: The VintasoftRectF structure that is to the right of the inequality operator.

Return Value

True if any of the X , Y, Width, or Height properties of the two VintasoftRectF structures are unequal; otherwise, false.

Requirements

Target Platforms: .NET 10; .NET 9; .NET 8; .NET 7; .NET 6; .NET Framework 4.8, 4.7, 4.6, 4.5, 4.0, 3.5

Reference

VintasoftRectF Structure
VintasoftRectF Members

Send Feedback