PanTool Class

In This Topic

Represents a visual tool for panning an image in image viewer.

Object Model

Syntax

'Declaration

Public Class PanTool
   Inherits VisualTool

public class PanTool : VisualTool

public __gc class PanTool : public VisualTool*

public ref class PanTool : public VisualTool^

Remarks

Image in image viewer can be panned as follows:

place the mouse to the desired position
press and hold the action button (ActionButton)
pull the cursor for panning the image

If ActionButton is set to right mouse button, context menu during action can be disabled with the DisableContextMenu property.

Example

This C#/VB.NET code shows how to set the PanTool as active visual in ImageViewer.

VB.NET


Class PanToolExample
    Public Sub SetPanToolAsActiveVisualToolOfImageViewer(viewer As Vintasoft.Imaging.UI.ImageViewer)
        ' create an instance of the PanTool class
        Dim panTool1 As New Vintasoft.Imaging.UI.VisualTools.PanTool()
        ' set the tool as the current tool of the ImageViewer
        viewer.VisualTool = panTool1
    End Sub
End Class


class PanToolExample
{
    public void SetPanToolAsActiveVisualToolOfImageViewer(
        Vintasoft.Imaging.UI.ImageViewer viewer)
    {
        // create an instance of the PanTool class
        Vintasoft.Imaging.UI.VisualTools.PanTool panTool1 =
            new Vintasoft.Imaging.UI.VisualTools.PanTool();
        // set the tool as the current tool of the ImageViewer
        viewer.VisualTool = panTool1;
    }
}

Inheritance Hierarchy

System.Object
Vintasoft.Imaging.UI.VisualTools.VisualTool
Vintasoft.Imaging.UI.VisualTools.PanTool

Requirements

Target Platforms: .NET 11; .NET 10; .NET 9; .NET 8; .NET 6; .NET Framework 4.8, 4.7, 4.6, 4.5, 4.0, 3.5

Reference

PanTool Members
Vintasoft.Imaging.UI.VisualTools Namespace

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